3u^2+16u+24=0

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Solution for 3u^2+16u+24=0 equation: 



3u^2+16u+24=0

a = 3; b = 16; c = +24;
Δ = b2-4ac
Δ = 162-4·3·24
Δ = -32
Delta is less than zero, so there is no solution for the equation

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